I have another few questions:
The value of x in Fe(NH4)2(SO4)2.xH2O can be found by determining the amount in moles of sulfate in the compound.
A 0.982 sample was dissolved in water and excess BaCL2 was added. The precipitate of BaSO4 was seperated and dried and found to weigh 1.17g.
Calculate the amount in moles of sulfate in the 0.982g sample of Fe(NH4)2(SO4)2.xH2O
What I have been doing is"
a). no. moles of the entire thing: 0.982 / 284.07 = 0.003456
b). (192.12/284.07) = 0.6763121766 [192.12 is the mass of (SO4)2
c) (a) * (b) =0.002 which i thought was the answer but the answer is actually 0.00501