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Topic: Newcomer to Chemistry and needing help identifying a compound  (Read 3299 times)

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Offline Panzer336

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Newcomer to Chemistry and needing help identifying a compound
« on: January 10, 2010, 06:02:39 AM »
Hi I am new to Chemistry and I am trying to identify a compund and was wondering if i could get some help.  My first thought was Methyloentane

          H    H    H
H3C     C    C    C    CH3
        CH3   H    H

Thanks in advance for any help

Offline bolo

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Re: Newcomer to Chemistry and needing help identifying a compound
« Reply #1 on: January 10, 2010, 06:23:22 AM »
2-methylpentane is correct.

Offline bingyucas

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Re: Newcomer to Chemistry and needing help identifying a compound
« Reply #2 on: January 10, 2010, 09:04:22 AM »
2-methylpentane

Offline srihari

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Re: Newcomer to Chemistry and needing help identifying a compound
« Reply #3 on: January 10, 2010, 09:08:19 AM »
hi buddy

You can use the ACD labs free software to draw structures else while drawing
bigger structures you may find difficult.

and the answer is right :)
life's game -play it

Offline scratfin

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Re: Newcomer to Chemistry and needing help identifying a compound
« Reply #4 on: January 12, 2010, 10:53:45 PM »
Hi I am new to Chemistry and I am trying to identify a compund and was wondering if i could get some help.  My first thought was Methyloentane

          H    H    H
H3C     C    C    C    CH3
        CH3   H    H

Thanks in advance for any help
Now, there is a problem with the other answers. Now, they are all correct but lack something. And explanation! Also, you may use the IUPAC website to find a chemical sketch program but I don't know where to find it exactly (haven't used it lately but you don't need to download it).

2-methylpentane is obtained because there is 1 carbon group (meth+yl) and it is at the 2nd carbon (you start numbering from the carbon closest to a carbon group). You get the pentane (as you seem to know) from the carbon chain.
So:

          H    H    H
H3C     C    C    C    CH3
        CH3   H    H
2-meth(yl)pent(ane)

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