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Topic: hybridization bonding.  (Read 3415 times)

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Offline narutodemonkill

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hybridization bonding.
« on: January 31, 2010, 06:38:47 PM »
H3C-CO-O-O-NOO
   C  D   E  F G  --> correspond to subscripts.

Nitrogen has double bond with one oxygen and carbon d has double bond with oxygen.


question what type of orbital describe thebond b/w CD and OE
CD has trigonal planar structure so has sp2 hybridization orbitals forming single bonds(sigma)
where as OE 2p orbital overlaps with this sp2 orbital to form single bond with carbon right

Offline Mitch

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Re: hybridization bonding.
« Reply #1 on: January 31, 2010, 10:46:36 PM »
I'm pretty sure OE is sp3.
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Offline narutodemonkill

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Re: hybridization bonding.
« Reply #2 on: February 01, 2010, 11:19:00 AM »
I'm pretty sure OE is sp3.

No I think Oxygen is SP because it forma 1 triple bond and one single bond.

Offline narutodemonkill

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Re: hybridization bonding.
« Reply #3 on: February 01, 2010, 11:19:46 AM »
I'm pretty sure OE is sp3.
sp3 would indicate it having a tetrahedral arrangement.

No I think Oxygen is SP because it forms 1 triple bond and one single bond.

Offline Schrödinger

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Re: hybridization bonding.
« Reply #4 on: February 01, 2010, 11:29:24 AM »
I'm pretty sure OE is sp3.

No I think Oxygen is SP because it forma 1 triple bond and one single bond.
Oxygen cannot form a triple bond.
Moreover, there are 2 atoms attached on either side of OE. It also has 2 lone pairs on it.
That has to make it sp3, not sp.

As a matter of fact, Oxygen does have a tetrahedral arrangement  ;)
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Offline narutodemonkill

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Re: hybridization bonding.
« Reply #5 on: February 01, 2010, 06:28:07 PM »
I'm pretty sure OE is sp3.

No I think Oxygen is SP because it forma 1 triple bond and one single bond.
Oxygen cannot form a triple bond.
Moreover, there are 2 atoms attached on either side of OE. It also has 2 lone pairs on it.
That has to make it sp3, not sp.

As a matter of fact, Oxygen does have a tetrahedral arrangement  ;)


o yeah that makes perfect sense thank you.

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