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Topic: Exercise on Titration  (Read 4010 times)

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Offline Szeck

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Exercise on Titration
« on: February 03, 2010, 05:54:27 AM »
Hi everyone!
Sry for my bad chemical english,
but i have a problem here....

"A solution of 0,4M K2Cr2O7 is added to another solution 0,5M of FeSO4 (Volume = 0,05l (50ml))
Calculate the volume of K2Cr2O7."

I set the reaction like so:
K2Cr2O7 + FeSO4 -->  K2SO4 + FeCr2O7
The formula to find the volume is: V1*M1 = V2*M2
So, 0,4x=0,5*0,05
The result is 0,0625litres.

I don't know if the reaction is correct...

Thanks in advance for the help.



Offline Schrödinger

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Re: Exercise on Titration
« Reply #1 on: February 03, 2010, 07:18:08 AM »
If the solution is acidic, then I think you should think of oxidizing the Fe2+ to Fe3+. Try writing the equations for that. (ionic equations will do, i guess)
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Offline Szeck

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Re: Exercise on Titration
« Reply #2 on: February 03, 2010, 07:38:02 AM »
Yes BUT,
my solution is not acidic, because the exercise doesn't say that there is an acid or a base.
So, I haven't set the reaction in the ionic form.

Do you think that the reaction is correct? I don't have any clear ambient...


Offline Schrödinger

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Re: Exercise on Titration
« Reply #3 on: February 03, 2010, 08:03:23 AM »
I don't know the exact reaction in a neutral medium, but something tells me that K2Cr2O7 will oxidize the Fe2+ to Fe3+.
"Destiny is not a matter of chance; but a matter of choice. It is not a thing to be waited for; it is a thing to be achieved."
- William Jennings Bryan

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