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Topic: Why [Cr(CN)6]4- has half-life less than 1 minute?  (Read 4894 times)

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Offline sahar58

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Why [Cr(CN)6]4- has half-life less than 1 minute?
« on: February 03, 2010, 09:26:56 PM »
[Cr(CN)6]4- is an inert complex. As i know inert complexes have half-lives more than 1 minute but Why [Cr(CN)6]4- has half-life less than 1 minute?

Offline Dolphinsiu

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Re: Why [Cr(CN)6]4- has half-life less than 1 minute?
« Reply #1 on: February 05, 2010, 12:01:09 PM »
For [Cr(CN)6]4-, it seems formal oxidation state is Cr(II), d4 system. According to Taube's expectation, it is inert. But when you compare it with [Cr(CN)6]3-, which is d3 system, that is much more coordinatively inert. Hence, [Cr(CN)6]4- is readily subjected to oxidation or pick up the solvent component.

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