[lisabella3686]

Hello everyone!

I was wondering if anyone could help me with these formulas.
I know that neutralization= acid + base -> salt + water, but in these 2 cases, I can't seem to figure out the rearrangement.

a)
KOH(aq) + CH4COOH(aq) -> salt (?) + H2O(l)

K+ + OH- + C + 3H+ + C + O2- + OH- ->


NH3(aq) + HI(aq) -> salt (?) + water (no O2 to create water???)

please help

thank you
b)

[arnyk]

For a), what ions do those compounds form in solution?

KOH --> K+ + OH-
CH3COOH --> CH3COO- + H+

That would be acetic acid with the CH3, but you wrote CH4 so...

Anywho those are the ions, now you can probably figure out the salt and the water pretty easily.

b)

Those substances are already in solution (aq) and therefore there is water present.

Again, figure out what they ionize into.

NH3 --> NH4+ + OH-
HI --> I- + H+

Can you see the salt?

[lisabella3686]

For a), what ions do those compounds form in solution?

KOH --> K+ + OH-
CH3COOH --> CH3COO- + H+

That would be acetic acid with the CH3, but you wrote CH4 so...

Anywho those are the ions, now you can probably figure out the salt and the water pretty easily.

b)

Those substances are already in solution (aq) and therefore there is water present.

Again, figure out what they ionize into.

NH3 --> NH4+ + OH-
HI --> I- + H+

Can you see the salt?

whoops, 3 and 4 are too close sometimes on the keyboard. I have CH3 written on my page.

KCH3COO + H2O?
potassium acetate

So then I have to do 2 equations for the b)?

NH3 + HI -> NH4 + I + OH
and then
NH4 + I + OH -> NI + H2O

nitrogen iodide..can I even make that?
I can't balance the O???

*modification*
NH3 + HI -> INH4 (whaa is that?) + H2O

[xiankai]

u cant balance the oxygen because u havent figured out the dissociation of ammonia. let me make it clear:

NH3 + H2O --> NH4OH  (altho its supposed to be aq. NH3, since in reality ammonium hydroxide does not exist. but it doesnt matter since u'll learn such stuff later.)

so, dont split up NH4+ and OH- !!! i hope its a mistake on your part now try balancing the equation.

your modification is slightly correct. put the cation in front and the anion behind and u get NH4I, ammonium iodide. sounds right doesnt it?

[lisabella3686]

u cant balance the oxygen because u havent figured out the dissociation of ammonia. let me make it clear:

NH3 + H2O --> NH4OH  (altho its supposed to be aq. NH3, since in reality ammonium hydroxide does not exist. but it doesnt matter since u'll learn such stuff later.)

so, dont split up NH4+ and OH- !!! i hope its a mistake on your part now try balancing the equation.

your modification is slightly correct. put the cation in front and the anion behind and u get NH4I, ammonium iodide. sounds right doesnt it?

NH4I..ya...that makes more sense.
I don't understand the whole pulling something from nothing. I can see that NH3 is a weak base, which would involve some sort of proton acceptor, but there just isn't any OH- in my equation. How can I just pull it out of my ass? (pardon my french)
In math, you can't just create sections of equation.
Am I to assume that it's there and just kinda make it appear in the finale, or 2 equations or what?  Please help. I appologise for being short. I'm just a little personally frustrated because I don't do well with "you should be able to figure this out on your own".

[xiankai]

good thing u noticed that. it is why NH4OH doesnt exist, and is rather written as aq. NH3.

however for high school chemistry purposes, u have to write it out as NH4OH.

[lisabella3686]

ok, so then
NH4OH + HI -> NH4I + H2O
NH4+ + OH- + I- + H+ -> NH4+ + I- + 2H+ + O2-

yes?

[arnyk]

Ok so you got the first one:

CH3COOH + KOH --> KCH3COO + H2O

b)

Here are the ionization reactions:

NH3 + H2O --> NH4+ + OH-

HI + H2O --> I- + H3O+

So here are your ions:

NH4+ + I- + OH- + H3O+ <--> NH4I + H2O (unbalanced )

Basically: NH3 + HI --> NH4I + H2O

Alrighty?

[lemonoman]

which doesn't look right because it's not a balanced equation.

NH₃ + H₂O --> NH₄⁺ + OH^-

NH₄⁺ + HI <--> NH₄I + H₂O

NH₄I is a salt: one ammonium ion and one iodide ion.

P.S. I notice that AGAIN arnyk and lisabella are a collaboration on this forum.  I woul dhave been here for it, but I went to play pool.

P.S.S. Our rant about lisabella's "Enthalpy" post made the top 10 in Chemical Forums history for number of replies haha

[arnyk]

Ok how about:

NH3  <--> NH4+ + OH-

HI <--> I- + H+

So:

NH3 + HI <--> NH4I

And water is pretty much there from the start anyways, you just have more of it by the end.

[lisabella3686]

thanx everyone!

and what can I say, I'm irresistable! Jk!

I love pool. 8 ball is good with me. 9 ball also works.
I have one more question:
please refer to my other post