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Topic: Question...Check my Answer  (Read 14064 times)

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Offline benworld

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Re: Question...Check my Answer
« Reply #15 on: February 16, 2010, 01:32:00 PM »
thats is what i did

g to mol  and mol to g

Offline maximus242

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Re: Question...Check my Answer
« Reply #16 on: February 16, 2010, 01:39:47 PM »
Yea so just calculate it and there you go

« Last Edit: February 16, 2010, 01:52:24 PM by maximus242 »

Offline benworld

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Re: Question...Check my Answer
« Reply #17 on: February 16, 2010, 01:42:56 PM »
Nacl is inert elements, it has no effect at all.

1. Found Mol of Bacl2 * 2H20

2. Take the mol and times it by mole of H20 Since it H20 is being decomposed.

3. Take Mole of H20 and convert new substance into grams

4. Take the answer and minus it by original mass

It seems pretty simple as that ?

Offline maximus242

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Re: Question...Check my Answer
« Reply #18 on: February 16, 2010, 01:51:54 PM »
Yea if you take the H20 weight and minus it from the original mixtures weight that will give you the weight of NaCl and BaCl2.

Offline benworld

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Re: Question...Check my Answer
« Reply #19 on: February 16, 2010, 01:58:17 PM »
Sounds..good..lol finally

36.00 g 2H20
------------  x 100 = 14% is how much dam 2H20 is
244.20

4.165 * 0.55 = 2.29075 g

2.29075 * 0.14 = 0.320705 g (2H20)

4.165 - 0.320705 = 3.844 g solid residu left ( bam...tell me if this is the answer ) :)

Offline maximus242

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Re: Question...Check my Answer
« Reply #20 on: February 16, 2010, 02:10:38 PM »
Ah you cant do this 4.165 * 0.55 = 2.29075 g

Its 55% by mole not by weight right? So you have to figure out what the moles are, then calculate the percentage of weight of BaCl2*2H2O, then convert it back to grams, then calculate weight of 2H2O.

You know there should be formulas for this in your textbook..

Offline benworld

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Re: Question...Check my Answer
« Reply #21 on: February 16, 2010, 02:16:01 PM »
no its by weight...It says BaCl2 * 2H20 is 55 % ... So its assume its weight... aka....saying if entire sample is 4.156 g , then 55% of mixture 4.165 is 2.29075 in grams ?

Am I making sense.


Offline maximus242

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Re: Question...Check my Answer
« Reply #22 on: February 16, 2010, 02:40:20 PM »
Oh lol ffs then it's rediculously easy. The other guy said it was by moles. Then yea you got it right as.

Offline DrCMS

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Re: Question...Check my Answer
« Reply #23 on: February 16, 2010, 02:52:18 PM »
Oh lol ffs then it's rediculously easy. The other guy said it was by moles. Then yea you got it right as.

Yeh but you still managed to make it more complicated by steering him in the wrong directions with your stupid answers for molecular weights.  Also nobody but you said it was 45:55 in mole ratio, sjb simply pointed out benworld was wrong to use 1:1 mole or mass ratio.  In future either make sure you are right or shut up.

Offline maximus242

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Re: Question...Check my Answer
« Reply #24 on: February 16, 2010, 06:17:36 PM »
He ended up with the right answer didnt he? I misunderstood something, I apologize for being a fallible, imperfect human being.

Theres no need to be rude.
« Last Edit: February 16, 2010, 06:35:58 PM by maximus242 »

Offline DrCMS

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Re: Question...Check my Answer
« Reply #25 on: February 17, 2010, 04:40:31 AM »
Believe me this is not me being rude if I wanted to be rude you'd know about it. 

Yes to ere is human but in this thread you have posted 8 times and of those 4 were incorrect and confused things.  If you are going to post pointing out somebody else is wrong then the least you can do is be sure they are wrong and you are right.  In your case the things you said were wrong were actually right and it was you who got it wrong.  It would have been simple for you to look up the molecular weights of water and barium chloride to check who was right but you didn't bother.  Those of us with more experience just know water is 18 etc.  You being wrong in half the things you say is not a good track record for helping somebody else.

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