The slowest step will always be the RDS
I agree, and I have written so above - giving a silly fire alarm in a store analogy.
and the division does not matter as it is just an expression obtain to get rid of the intermediate.
Yes it does matter. You can't use an algebraic manoeuvre if it leads to an incorrect answer
I would not consider proton as intermediate as it is used it the last step.
Yes it is an intermediate. The fact it is used in the last step is irrelevant.
The confusion, I believe arises, because the possible reaction steps have all been laid out at the start.
If we look at the overall equation of the decomposition of nitranamide
O + H2
is not visible in the overall equation, and it definitely isn't an initial reactant, so it can't be part of the rate equation. This behaviour is seen in all the examples linked to in the above posts.
Furthermore the RDS is not in an equilibrium thus making the rate law even less direct.
Sorry, I don't see your point
Correct my argument if i am wrong.
I believe I have
I may be wrong but I think I have laid my argument out clearly in the posts above. I would be very grateful if anyone can expose a flaw in my argument by pointing out which bit is wrong and providing a reference as to which part of my explanation is wrong. Currently I'm confident in my argument for the reasons given in my several posts above.