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Topic: Equilibrium problem w/ quadratic  (Read 4155 times)

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Offline michaelt817

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Equilibrium problem w/ quadratic
« on: February 28, 2010, 10:43:44 PM »
At a certain temperature, K = 9.1  10-4 for the following reaction.

FeSCN2+(aq) reverse reaction arrow Fe3+(aq) + SCN -(aq)
Calculate the concentrations of Fe3+, SCN -, and FeSCN2+ in a solution that is initially 4.0 M FeSCN2+.

ok so im not sure how to choose which answer after solving the quadratic equation.

9.1e-4 +/- sqroot(-9.1e-4)^2- 4(1)(.00364)/ 2(1)... this equals 9.1e-4 +/- .120664825 / 2(1)

For + i get .06078 (right answer)
For - i get .059877

NVM I put the - part wrong in the calculator.. DELETE!!

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