A. 209

B. 205

C. 194

D. 163

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**ANSWER: A. 209Solution: Total number of ways of selecting 4 livestock from 6 cows and 4 buffalos: **

A. 7/9

B. 5/12

C. 1/6

D. 5/9

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**ANSWER: D. 5/9 **

A. 2400

B. 3600

C. 7200

D. 1600

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**ANSWER: B. 3600 Solution: 3600. The number is perfect square of 60.It is divisible by 36 24 and 20. Only two numbers 3600 and 7200 fit these conditions.It is clear that 3600 is the smaller number.**

A. 34.25

B. 35

C. 33.25

D. 34.25

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**ANSWER: D. 34.25 Solution = Average runs scored by Virat Kohli in 10 matches: Total runs scored/10—(1)Average runs scored by Virat Kohli in 6 matches: (Total runs in 6 matches)/6=> 42 = Runs/6=>252 runsUsing (1):=>38.9 = Runs/10=>389 runs Runs scored in rest 4 matches: 389 - 252 runs=> 137 runs Average runs scored by Virat Kohli in 4 matches: 137/4 = 34.25 runs**

A. 108

B. 86

C. 74

D. 92

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**ANSWER: A. 108 Solution: It is given that 243 has been divided into 3 numbers x y and z for instance.Second condition mentioned in the question is:=> x/3 = y/4 =z/2Clearly the biggest number is y. So let us solve w.r.t. y.=> x = 3y/4=> x =3z/2=> z = y/2=> x+y+z = 243=> y/2 + 3y/4 + y = 2439y/4 = 243=> 243*4/9=> 108**

A. 375

B. 1175

C. 675

D. 2125

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**ANSWER: B. 1175 Answer: Total number of students who appeared for the examination: 250035% of these students failed in Engish: (35/100)*2500 = 87542% candidates failed in Hindi: (42/100)*2500 = 105015% candidates failed in both English and Hindi: (15/100)*2500 = 375Now, to find out the number of candidates who failed in either of the two but not both:=> No. of students who failed only in English: 875 - 375 = 500=> No. of students who failed only in Hindi: 1050 - 375 = 675=> 500 + 675 =>1175**

A. 12

B. 24

C. 6

D. 8

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**ANSWER: A. 12 Solution: We know that 2**

A. 25

B. 33.333

C. 66.667

D. 40

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**ANSWER: C. 66.667 Solution: Let listed price of the product be x Hence at 25% discount rate the Cost Price will become: 3x/4Now to make an overall profit of 25% over listed price:SP = CP+(25/100)CP=> SP = x+x/4=>SP = 5x/4=>Selling Price over Cost price: (5x/4)-(3x/4)=>x/2=>%Selling price over Cost price: (x/2)/(3x/4)*100=>66.67%**

A. Rs 2250

B. Rs 1550

C. Rs 450

D. Rs 900

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**ANSWER: D. Rs 900 Solution = It is given that business partnership is independent of time in this case as all the investors have invested their money for same amount of time.Let A’s capital be x, B’s capital be y and C’s capital be z.=>x+y+z = 4650=> 4x = 6y = 10z=>C’s share is z so let us solve the question w.r.t. z=>x = 5z/2=>y = 5z/3=>(5z/2)+(5z/3)+(z) = 4650=>31z = 4650*6=>z = 900**

A. 12 days

B. 3 days

C. 4 days

D. 6 days

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**ANSWER: B. 3 days Solution:More no of people: Less days (Inverse Relationship)More work: More days (Direct Relationship)Ratio is given:Persons: 1 :: 2Work 1 :: 1/2Time 12 :: xSolution of this can be explained by solving this ratio by the sort of relationships they possess with time.1*1/2*12 = 2*1*x=> x = 3 days**

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