[tanner.e]

For a reaction
CO+NO2-->CO2+NO
The activation energy for the forward reaction is 135kJ/mol of CO reacted.

a) Determine the heat of reaction?

Co=  -110.5      
NO2= 33.1
CO2= -393.5
NO=  90.3      
Equals (-77.4)-(-303.2)
= -226kJ/mol

b) from the data given, and the deltaHr for the reaction, determine the activation energy for the reverse reaction.

For this one  I'm a bit confused would I add -226 to 135?

c) draw and label a potential energy diagram for the reaction.

I need to find,
heat of reactants= 135kJ/mol?
Activation energy= unsure how to obtain this?
Activate complex= ?
product=?
Delta H= -226kJ/mol?

any help with this would be so beneficial thank you.

[cliverlong]

For a reaction
CO+NO2-->CO2+NO
The activation energy for the forward reaction is 135kJ/mol of CO reacted.

a) Determine the heat of reaction?

CO=  -110.5      
NO2= 33.1
CO2= -393.5
NO=  90.3      
Equals (-77.4)-(-303.2)
= -226kJ/mol

I believe you have the numbers round the wrong way

From: http://www.docbrown.info/page07/delta1H.htm

 :delta: H_r =  (sum) H _prod -  (sum) H _react

b) from the data given, and the deltaHr for the reaction, determine the activation energy for the reverse reaction.

For this one  I'm a bit confused would I add -226 to 135?

c) draw and label a potential energy diagram for the reaction.

I need to find,
heat of reactants= 135kJ/mol?
Activation energy= unsure how to obtain this?
Activate complex= ?
product=?
Delta H= -226kJ/mol?

any help with this would be so beneficial thank you.

For both parts b) and c) a simple diagram such as the one found in section 1.1a of : http://www.docbrown.info/page07/delta1H.htm will really help

From the diagram, can you see the relationship between:

 :delta: H _forward
 :delta: H _reverse
E_a

?

Clive