for the reaction
H2 (g) + CO2 (g) <-----> CO (g) + H20 (g)
Kc = 0.18 at 500 degrees
calculate the concentration of H2 in an equilibrium mixture in which the molar concentrations are 0.011 mol dm-3 CO2 , 0.0030 mol dm-3 H2O and 0.041 mol dm-3 CO.
Kc = [CO] [H20] / [H2] [C02]
0.18 = 0.041 x 0.0030 / [H2] x 0.011
[H2] = 0.062
PLEASE CAN SOMEONE LET ME KNOW IF THIS IS RIGHT?!