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Topic: PH of a buffer made by mixing two solutions  (Read 9776 times)

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Offline claire18

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Re: PH of a buffer made by mixing two solutions
« Reply #15 on: April 21, 2010, 01:52:57 PM »
What can i do to make it right?

Offline Matias Ekstrand

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Re: PH of a buffer made by mixing two solutions
« Reply #16 on: April 21, 2010, 02:58:46 PM »
Your equation is wrong:
http://en.wikipedia.org/wiki/Henderson%E2%80%93Hasselbalch_equation

and this:

You're right about which chemical is the acid and which is the conjugate base, but make sure to take into account that you mix two solutions and change the volume (which changes the concentrations).
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Offline claire18

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Re: PH of a buffer made by mixing two solutions
« Reply #17 on: April 21, 2010, 03:46:41 PM »
thanks, is my answer way off then?

Offline claire18

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Re: PH of a buffer made by mixing two solutions
« Reply #18 on: April 21, 2010, 06:53:57 PM »
0.050 x 200 = 10
0.100 x 100 = 10

4.202 + log (10/10)
PH= 4.202

Is this one right?

Offline Matias Ekstrand

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Re: PH of a buffer made by mixing two solutions
« Reply #19 on: April 22, 2010, 12:23:57 AM »
Not really.

Do you know how to make calculations on a dilution?
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Offline Borek

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Re: PH of a buffer made by mixing two solutions
« Reply #20 on: April 22, 2010, 03:00:36 AM »
The real question is - if it is right, do you understand why? I doubt.
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