December 13, 2024, 12:48:56 AM
Forum Rules: Read This Before Posting


Topic: Potassium Manganate 7 titration with a mixture of iron 2 and iron 3 sulphates  (Read 9154 times)

0 Members and 1 Guest are viewing this topic.

Offline Rhonut

  • New Member
  • **
  • Posts: 4
  • Mole Snacks: +0/-0
Ok, so i have this question i'm doing for revision and i am a bit stuck. The answer on it's own is a bit useless though, i need more how to get to it and why. Anyway, here's the question:

A solution contains iron (ii) and iron (iii) sulphates, 20cm3 of this solution just reduced 19.5cm3 of 0.0200 M Potassium Manganate (vii) in acid solution. After reduction (complete), a further 20cm3 of the solution required 28.7cm3 of the potassium manganate (vii). Calculate the concentration of each sulphate in g.1-1 present in the original solution.

I've started by getting the number of moles of manganate from the first reduction, if that's remotely correct.

Offline BluRay

  • Full Member
  • ****
  • Posts: 154
  • Mole Snacks: +9/-2
Sorry, it's a homework...

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27884
  • Mole Snacks: +1815/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
What is being oxidized during first titration?

What is being oxidized during second titration?
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Rhonut

  • New Member
  • **
  • Posts: 4
  • Mole Snacks: +0/-0
I'm not quite sure, that is all the information the question gives and there are no questions before that it leads from. I'm assuming the manganate is reduced, and the iron 2 is being oxidized, but how you'd get the concentration of iron 3 i don't know and why two titrations are necessary i don't know. I think the question itself is worded in a confusing way, but all i can do is try to decipher it...   I've come up with some half equations, but not sure if they're the right way to go about this:

  • 5Fe2+  :rarrow: 5Fe3+ + 5e-
  • MnO4- + 8H+ + 5e-  :rarrow: Mn2+ + 4H2O

I've got the number of moles of manganate used in the first titration as 0.00039 and in the second titration as 0.000574, If that's of any use..

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27884
  • Mole Snacks: +1815/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
iron 2 is being oxidized

That's correct. It is oxidzed in both titrations. Do you know why results of both titrations are different? There is a very important hint in the question that explains it.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Rhonut

  • New Member
  • **
  • Posts: 4
  • Mole Snacks: +0/-0
It's what i'm struggling to understand. I think it may be due to the iron 3 formed during the first oxidation of iron 2, if that makes sense, i'm not sure. Does only the iron 2 get oxidised the first time and the iron 2 and iron 3 get oxidised the second time or something?

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27884
  • Mole Snacks: +1815/-412
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Does only the iron 2 get oxidised the first time and the iron 2 and iron 3 get oxidised the second time or something?

Yes!

Note that original solution contains both Fe2+ and Fe3+ and only Fe2+ can be oxidized. Then you pepare solution for the second titration:

After reduction (complete)

so at this moemnt it doesn't contain Fe3+, as it was all reduced to Fe2+.

You see now what have been titrated in the first titration and what have been titrated in the second?
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline Rhonut

  • New Member
  • **
  • Posts: 4
  • Mole Snacks: +0/-0
Ah i think i can see clearly now that the rain has gone, or the Fe3+ rather. The difference in manganate volumes is the amount used to work out how much Fe3+ there was, as the Fe2+ oxidized by that difference in manganate is the amount of Fe3+. I plugged all the numbers in and my answers look relatively within reason, Thanks Borek!

Sponsored Links