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Topic: Determination of an Unknown Salt !  (Read 6193 times)

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Offline ecestudent

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Determination of an Unknown Salt !
« on: April 15, 2010, 03:54:06 PM »
For this lab I was given an unknown salt and I so far I have done precipitation tests, found the pH, and found out it decomposes with heat when I did a waters of hydration lab and after about 8 min my unknown was gone.

So far I have:

Flame test seemed like the cation was sodium but I am going to re-do this again tomorrow, it didnt seem to be "enough" orange flame, I then used colbalt glass and didnt see anything. But I want to double check.

pH= 6.02 so it must be a neutral salt

UK+ NaOH= no precipitate
UK+ Na3PO4= no precipitate
UK+ Na2CO3= No precipitate
so it must be a first row cation
   *and when I added a few drops of HCl to the unknown gas was evolved as it seemed, but there were no bubbles. it was just a small amount of white looking smoke. I am not sure what to make of it.
 
then:

UK+ AgNO3= milky white precipitate
UK+ Pb(NO3)2= white precipitate

so far I think the cation is Na+, which is why I want to make sure with another flame test because all the first rows have great color, but the range of anions is still wide.

I am not sure what to conclude or what other tests to do, anyone have any suggestions on possible cations/anions and tests I should do? any help is appreciated!

Offline Borek

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Re: Determination of an Unknown Salt !
« Reply #1 on: April 15, 2010, 05:22:29 PM »
UK+ AgNO3= milky white precipitate
UK+ Pb(NO3)2= white precipitate

Quote
the range of anions is still wide.

Really?
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Offline ecestudent

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Re: Determination of an Unknown Salt !
« Reply #2 on: April 15, 2010, 06:21:08 PM »
Cl-, I-, Br-, or a sulfate, maybe a fluoride. ok so maybe not soo many. but I'd rather narrow it down more. I still dont even have my cation all the way down yet. just only that it is a first row

Offline UG

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Re: Determination of an Unknown Salt !
« Reply #3 on: April 15, 2010, 06:38:37 PM »
If you think it is a sulfate, try adding BaCl2 to it and see if there is a precipitate.
Just my own two cents, it's probably either a chloride or a bromide. Try adding dilute ammonia to the precipitate you got from adding AgNO3, if it is AgCl, it will dissolve.

Offline ecestudent

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Re: Determination of an Unknown Salt !
« Reply #4 on: April 15, 2010, 06:43:50 PM »
I thought about using BaCl2 but I couldnt find any in the stock room. Im going to look again but thanks for the second suggestion, Im going to try that

Offline Borek

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Re: Determination of an Unknown Salt !
« Reply #5 on: April 15, 2010, 06:45:49 PM »
Cl-, I-, Br-

Both precipitates were white?
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Offline ecestudent

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Re: Determination of an Unknown Salt !
« Reply #6 on: April 15, 2010, 06:53:46 PM »
yup, what are you getting at?

Offline UG

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Re: Determination of an Unknown Salt !
« Reply #7 on: April 15, 2010, 07:12:52 PM »
Lead iodide is yellow.

Offline ecestudent

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Re: Determination of an Unknown Salt !
« Reply #8 on: April 15, 2010, 07:17:04 PM »
ok so I- is out, thanks

Offline skyjumper

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Re: Determination of an Unknown Salt !
« Reply #9 on: April 15, 2010, 08:50:20 PM »
Lead bromide melts at about 367 to form a clear liquid, while lead chloride melts at +500 degrees, try a melting point test on the lead precip

Offline Borek

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Re: Determination of an Unknown Salt !
« Reply #10 on: April 16, 2010, 02:48:27 AM »
Lead bromide melts at about 367 to form a clear liquid, while lead chloride melts at +500 degrees, try a melting point test on the lead precip

Checking if the precipitate dissolves in a hot solution is much easier.
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Offline NaOH

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Re: Determination of an Unknown Salt !
« Reply #11 on: April 16, 2010, 01:03:12 PM »
Maybe its ammonium chloride, on class I made a reaction of ammonium chloride solution and silver nitrate solution and it gave a white percipitate.

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