[ILoveISO]

Dry ice sublimes at -78.5 degrees C under 1atm pressure. Indicate the signs of change in H, G and S for the reaction CO2(g) --> CO2(s) (1ATM)

Temp:                      H                    G              S

0 degree                  - (why neg?)    +               -   (why is this neg? shouldn't it positive at 0 degrees isn't it still a solid? so less random)

-78.5 degree            -                     0 (why zero...) -

-100 degree             -                     -               -


Basically the change in free energy column I got all wrong and don't get how to find change in G and the q's I put in brackets can anyone help

[Matias Ekstrand]

At 0 degrees C you are at a temperature above the sublimation point. Does that mean the reaction should be shifted towards the left or right? How does this affect ΔG?

ΔH is negative because this change of physical state gives away heat (the opposite reaction requires heat if that is easier to understand).

Can you tell me what happens to entropy when performing the reaction that goes to the right?

ΔG is 0 at -78.5 degrees C because you will reach an equilibrium at this temperature where no net reaction takes place.

[ILoveISO]

But at 0 it hasn't sublimed yet so isn't it in a solid state still?

Also if at -78.5 G is 0 then why is at 0 degree it's positive and at -100 is negative? How do you determine G?

[Matias Ekstrand]

0 > -78.5

G describes if the reaction to the right is spontaneous or not. Take a look at your reaction again, and note the physical states.

[ILoveISO]

Neg G = nonspont? and Pos G = spont?

Still don't get why H is - at 0 degrees...

[Matias Ekstrand]

Neg G = nonspont? and Pos G = spont?

Other way around. A negative G means spontaneous reaction to the right.

Still don't get why H is - at 0 degrees...

ΔH does not depend on temperature.

[MrTeo]

Still don't get why H is - at 0 degrees...

ΔH does not depend on temperature.

I'm not very sure about that... we can only consider it constant for small temperature gaps...

[Matias Ekstrand]

Still don't get why H is - at 0 degrees...

ΔH does not depend on temperature.

I'm not very sure about that... we can only consider it constant for small temperature gaps...

Thank you for that clarification