[sjbyrne]

A voltaic cell utilizes the following reaction and operates at 298K:  3Ce^4+(aq) + Cr(s) --> 3Ce^3+(aq) + Cr^3+(aq).  What is the emf of the cell when [3Ce^4+] =  0.11 M,[3Ce^3+] =  1.6 M,, and [Cr^3+] =  2.7 M?

I tried using the Nernst equation but my answer was incorrect.  Here were my calculations:
2.35 - (8.3145*298)/(3*96485) * ln(.11^4)/(1.6^3 * 2.7).  So what happened?  Why is this not correct?  I feel like I must have messed up my units somewhere, but I just can't seem to find it.

[sjbyrne]

Wow, I redid my calculations and I got it right.  The mistake was that I messed up my Q value and put reactants/products instead of products/reactants.