^{130}I decays by emission of beta particles to form stable ^{130}Xe. A 3.00 g iodine sample containing some I-130 was recorded as having 2464 disintegrations per min. k = 0.00094 min -1. How many radioactive I-130 atoms are present in the sample?

I'm thoroughly confused with this question. I started with the formula R=kN with R being the disintegrations per time, k being the decay constant and N being the number of radioactive nuclei (a bit confused on what N really means).

Plugging in what I have (R=2464, k=0.00094), I found "N" to be 2621276.596. From there, I'm not sure how to find the number of radioactive I-130 atoms present in the sample. I've tried incorporating Avogadro's number but I think that may be the wrong direction to go. I've also tried dividing the disintegration number by the amount of grams of the same present.

I've also tried using t1/2=ln2/k which just gave me the half life time which leads me to a dead end.

All the methods I've tried so far resulted in the wrong answer. Maybe I'm not understanding the question. Can someone shed some light into this?