[ashon1980]

Hello everyone,
I am self studying chemistry to try and get ahead for chem 1 in the fall this year. I never took chemistry in highschool, so I have almost no foundation for chemistry work. That being said, I am making progress. Three days ago I thought trial and error balancing equations was the hardest thing ever

Now that I have a good handle on balancing, I have moved onto Stoichiometry, and  I have ran across a brick wall pretty quickly.

In the below problem, I am fine until the 1b problem. I do not understand where 1mol Na/23g Na  comes from. Where did the author of this problem come up with 23g Na.

Otherwise I understand the math fine

Thanks,
Michael

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How many moles of chlorine gas (Cl2) would react with 5 moles of sodium (Na)
       according to the following chemical equation? (Balance equation.)

                                                  2Na + Cl2 --> 2NaCl

      [5 mol Na][1 mol Cl2]  =  2.5 mol Cl2
                              [2 mol Na]

1b)  Using the equation (after it is balanced) above, determine the amount of product that 
       can be produced  from 24.7 g Na. 

        [24.7g Na][1 mol Na][2 mol NaCl][58g NaCl   ]  =  62 g NaCl
                         [23 g Na  ][2 mol Na   ][1 mol NaCl]

1c)  How many molecules of product would be produced from 24.7g Na?

       [24.7g Na][1 mol Na][2 mol NaCl][6.023 E23 molecules NaCl   ]  =  6.5 E23 NaCl

[ashon1980]

Never mind. I  should have looked at the periodic table sooner.