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Topic: Help on Normality / equivalent weight Question  (Read 18652 times)

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Offline cshieh1231

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Help on Normality / equivalent weight Question
« on: May 25, 2010, 04:15:09 PM »
I have to make 0.1 N of sodium thiosulphate from sodium thiosulphate anhydrous (158.11 g/mol) to react with 0.1 iodine solution.


I thought the equation is

Na2S2O3 + I2  :rarrow: 2 NaI + 2 Na2S4O6

Some website said Sodium Thiosulphate has 1:1 ratio for molarity : normaility.

I don't know why sodium thiosulfate only use one sodium to react with iodine.

Offline Borek

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Re: Help on Normality / equivalent weight Question
« Reply #1 on: May 26, 2010, 03:03:41 AM »
Your reaction is not balanced. Could be a typo.

I don't know why sodium thiosulfate only use one sodium to react with iodine.

Sodium? Sodium is just a spectator.

What is normality of 0.1M I2 solution?
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Offline cshieh1231

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Re: Help on Normality / equivalent weight Question
« Reply #2 on: May 26, 2010, 04:20:00 PM »
Your reaction is not balanced. Could be a typo.

I don't know why sodium thiosulfate only use one sodium to react with iodine.

Sodium? Sodium is just a spectator.

What is normality of 0.1M I2 solution?

Ya it was a typo

2 Na2S2O3 + I2   2 NaI + 2 Na2S4O6

the normality of Iodine solution is 0.1 N

What I was trying to do is finding the % Sodium Lauryl Sulfate experiement.

In the wet analytical chemistry book instructed me to first run a blank experiment.  In a 50 ml water, add in 10 ml acetic acid, then add 10 ml of 0.1 N iodine solution.  (I think the acetic acid just making the water acidic, so the iodine would not react with water).  Then titrate the solution with 0.1 N of Na2S2SO3.

Then in the second run.  Add 2.0 g of sodium lauryl sulfate (SLS) solution in the water/iodine/acetic acid solution.  Suppose the SLS's sodium will react with the iodine in the solution before the titration.  Therefore, we should actually use less of 0.1 N Na2S2SO3 to titrate the iodine solution.

I was going to run a couple standards of 5%, 10%, 15%, 20%, and 30% of SLS solution, then make the calibration curve to compare my sample.

But now i am running into some quesitons.

1. How do I get the 0.1 n of Na2S2SO3 solution? The F.W. is 158.11 g/mol. I want to make into 500mL.

So I was using 0.5 * 0.1 = 0.05 mol.  Then I don't really know why in this case, everyone said 0.1 N of Na2S2SO3 equals to 0.1 M Na2S2SO3.

2. Since I really am just making a calibration curve, I suppose that even if I miscalculated the concertration of Na2S2SO3, I would still be okay because I am just using the amount of my Na2S2SO3 solution need to titrate the left over iodine in the solution after it react with SLS.  However, I still can't get the curve right...



Offline Borek

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Re: Help on Normality / equivalent weight Question
« Reply #3 on: May 26, 2010, 04:36:18 PM »
What is normality of 0.1M I2 solution?

the normality of Iodine solution is 0.1 N

Is it? How many electrons does one I2 molecule need?

http://www.titrations.info/iodometric-titration
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