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Topic: OMG Help  (Read 4073 times)

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Offline World

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OMG Help
« on: May 27, 2010, 11:22:43 PM »
Anyone that knows graphing really well, can you graph this:
x2-10x-8y+25=0
or
(x-5)2=-8y

Offline sjb

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Re: OMG Help
« Reply #1 on: May 28, 2010, 01:38:51 AM »
Which, as your two equations are not identical.

In any event, why not set up a table

x= -10; y = ?
x= -9; y = ?
...

etc

Offline skyjumper

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Re: OMG Help
« Reply #2 on: May 28, 2010, 04:50:22 PM »
Start by putting the equation above in standard form. (I just tested on this today :3) Then it will be clearer. (Hint: What is it, an elipse, circle, hyperbola, etc.) and same with the second. (Its parabolic). 


Offline fish2s

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Re: OMG Help
« Reply #3 on: August 10, 2010, 06:03:51 PM »
Rearange to give y = 0.125*(x-5)2 therefore touches the graph at (5,0) crosses at (0,[25/8]) and is a parabola.

Offline darko

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Re: OMG Help
« Reply #4 on: August 11, 2010, 08:46:06 AM »
can you use some of mathematical programs?
,
that is using Mathematica, with very simple program:
f[x_] = (x^2 - 10 x)/8
Plot[f
  • , {x, -10, 10}]


You can try with changing of {x,min,max} or use Manipulate function, any other questions?

oh, it is a wrong function it shold be (x^2 - 10 x+25)/8, but principles are the same
« Last Edit: August 11, 2010, 09:00:57 AM by darko »

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