I have been doing an assignment, and I finished most of the questions, but there are a couple I just don't know how to do. I don't even know where to start. I don't want anyone to give me just the answers, but if someone could work through these problems with me, I would really appreciate it. That way I'll know how to answer questions like these come exam time.
The first question:
Write a balanced chemical equation for the oxidation of Ag(s) by concentrated nitric acid. Two products of the reaction are NO2 (g) and Ag+ (aq). What is the oxidising agent and what is the reducing agent? I tried to take a stab at the equation, but I'm not sure if it's right. I got this: Ag(s) + 2HNO
3(aq)
Ag
+(aq) + 2NO
2 +H
2O(l). I think a big part of my problem is that I have no idea how to identify oxidising and reducing agents.
The second question:
Use the standard reduction potentials below determine which compound or ion is the best oxidizing agent?
Cl2(g) + 2 e- 2 Cl-(aq) Eº = +1.36 V
Ag2+(aq) + e- Ag(s) Eº = +0.80 V
Fe+(aq) + 2 e- Fe(s) Eº = -0.44 V This one I just don't have a clue about. If someone could work through this and show me how to solve it, I would be really grateful.
Third question:
Write a balanced chemical equation for the following reaction in a basic solution. H2O2(aq) + Cr(OH)3(s) H2O + CrO42-(aq). I think I can figure out how to write the actual equation, but according to my textbook, to do this I need to know the 2 half reactions, and I don't know how to identify those.
Fourth question:
Consider the following half-reactions:
F2(g) + 2 e- 2 F-(aq) Eº = +2.87 V
Cu2+(aq) + 2 e- Cu(s) Eº = +0.337 V
Sn2+(aq) + 2 e- Sn(s) Eº = -0.14 V
Al3+(aq) + 3 e- Al(s) Eº = -1.66 V
Na+(aq) + e- Na(s) Eº = -2.714 V
Which of the above compounds or ions are able to reduce Al3+? Once again, I just have no idea.
Last question:
Calculate the cell potential, at 25 ºC, based upon the overall reaction 3 Fe3+(aq) + Al(s) -> 3 Fe2+(aq) + Al3+(aq) if [Fe3+] = 0.300 M, [Fe2+] = 0.150 M, and [Al3+] = 0.300 M. The standard reduction potentials are as follows:
Fe3+(aq) + e- Fe2+(aq) Eº = +0.771 V
Al3+(aq) + 3 e- Al(s) Eº = -1.66 V I think this one involves the use of this equation E = Eº - 0.0592/
n log Q, but I don't know for sure, and if it does I'm not sure what the Q is supposed to stand for.
Any help that anyone could give me would be greatly appreciated, I'm running against the clock here. I really did try, but by the time I was ready to pull my hair out, I figured I should get some help.
These are due Monday the 1st of June, so any help before then would be great.