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Topic: practical exam (acid-base titration)  (Read 6314 times)

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Offline student12345

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practical exam (acid-base titration)
« on: May 31, 2010, 05:36:33 PM »
A known mass of a diprotic or triprotic acid is dissolved in water to make a precise solution. Samples of this solution are titrated with a standard solution of NaOH. The data generated is used to determine the molar mass of the acid.

I understand titration, however I am unclear as to how I know how much mass is dissolved in each sample I am titrating. I need the mass in order to solve for molar mass, but I only know the initial mass of the solid, and not the mass dissolved in each separate sample used in the titration.  Thanks!
« Last Edit: May 31, 2010, 05:52:27 PM by student12345 »

Offline Borek

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Re: practical exam (acid-base titration)
« Reply #1 on: May 31, 2010, 06:11:18 PM »
Are you given volume of the solution and volumes of the titrated samples?
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Offline student12345

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Re: practical exam (acid-base titration)
« Reply #2 on: May 31, 2010, 06:27:13 PM »
Since I am making the original solution, I am pretty sure I determine the volume, probably around 100mL, and I will also determine the volume of samples, probably around 10 mL.

Offline Borek

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Re: practical exam (acid-base titration)
« Reply #3 on: May 31, 2010, 06:53:24 PM »
Use this information to calculate mass of acid dissolved in each of the samples.

It won't be "volume around", you should use volumetric glassware to measure exact volumes.

http://www.titrations.info/pipette-burette
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Offline student12345

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Re: practical exam (acid-base titration)
« Reply #4 on: May 31, 2010, 07:07:26 PM »
Ok thank you. I am planning on using a pipet, I am just not sure yet what the volumes will be. So should I cross multiply to find the mass in each sample? For example if 20 grams are dissolved in the first 100mL, then 2g will be in 10mL?

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Re: practical exam (acid-base titration)
« Reply #5 on: May 31, 2010, 07:15:43 PM »
Yes.
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