[BJB]

Hi every one ,,
I hope all of you are fine .
ok. let us start

Q : At equilibrium, the pressure of the reaction mixture
    CaCO_3(s)     CaO_(s)  +  CO_2(g)
    is 0.105 atm at 350C. Calculate K_p & K_c for this reaction.


THE END

[OrganicSynthesis]

What is the expression for Kc and Kp for the reaction?

[19kevin87]

Not sure whether it's correct or not..

K_p = P_CO2
therefore K_p = 0.105 atm

Kc = [CO₂]
since only the pressure is provided, use the formula:
PV = nRT
n/V = P/RT
times MW of CO2 on both side you'll get:

nxMW / V = P/RT
and since nxMW/V = concentration of CO2
therefore Kc = P/RT