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Topic: How to balance organic ox-red reaction  (Read 3672 times)

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Offline ikariotis

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How to balance organic ox-red reaction
« on: June 03, 2010, 05:17:35 PM »
Hey!

Please help me balance following formula

C7H5NO3 + KMnO4  :rarrow: C7H5NO4

Ox: .
Red: ...

Total: .

No representation of electron-es in the total reaction.

Offline Jorriss

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Re: How to balance organic ox-red reaction
« Reply #1 on: June 04, 2010, 12:22:46 AM »
Where's your Manganese in the products?

Offline Borek

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Re: How to balance organic ox-red reaction
« Reply #2 on: June 04, 2010, 04:10:14 AM »
Obviously this is just a scheme that has to be filled up with lacking substances.

First of all - do you know what are conditions (acidic, neutral, basic) of the reaction?
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Offline ikariotis

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Re: How to balance organic ox-red reaction
« Reply #3 on: June 04, 2010, 05:59:19 AM »
the problem is just an oxidation whitout any conditions, but we have to do an redoxreaction scheme.

My example

Ox: MnO4- + 4H+ + 3e-  :rarrow: MnO2 + 2H2O
Red: C7H5NO3 + H2:rarrow: C7H5NO4 + 2H+ + 2e-

When I do like this I am gonna have electron-es on my total reaction so how can I eliminate this problem and still balance the reaction?

Offline Schrödinger

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Re: How to balance organic ox-red reaction
« Reply #4 on: June 04, 2010, 07:15:09 AM »
If you want to eliminate the electrons, then multiply each reaction by suitable factors (Least Common Multiple LCM) that will make the number of electrons equal in both the half reactions.  Then just add the reactions.
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Offline Borek

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Re: How to balance organic ox-red reaction
« Reply #5 on: June 04, 2010, 11:40:50 AM »
the problem is just an oxidation whitout any conditions

So it can't be done, as products of permanganate reduction depend on the pH.


Quote
Ox: MnO4- + 4H+ + 3e-  :rarrow: MnO2 + 2H2O
Red: C7H5NO3 + H2:rarrow: C7H5NO4 + 2H+ + 2e-

You got Red & Ox reversed.
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Offline Schrödinger

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Re: How to balance organic ox-red reaction
« Reply #6 on: June 04, 2010, 01:56:20 PM »
Quote
Ox: MnO4- + 4H+ + 3e-  :rarrow: MnO2 + 2H2O
Red: C7H5NO3 + H2O  :rarrow: C7H5NO4 + 2H+ + 2e-

You got Red & Ox reversed.
I didn't notice that   :-[
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