[silentelysium]

I'm not quite sure how to approach this question but I tried anyway.

Use the following energies of atomic orbitals for Cr to calculate the energies of Cr K(alpha) X-ray transitions. Identify whether these transitions will be observed in distinct lines.
K=5989.2 eV
L(I)=694.6 eV
L(II)= 583.7 eV
L(III) = 574.5 eV


I know that K(alpha) transitions due to the relaxation from L(III) --> K so I decided to do this:

5989.2 - (574.5 + 583.7 + 694.6) = 4136.4eV = 4.14 keV (I have a feeling this is wrong so please help me rectify it)

The emission lines are identifiable because the electron gun is aroung 5-20 keV so it is possible to generate these energies...

Is this correct? Am I going towards the right track? 

Thanks.