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Topic: Calculating turn over number of an Enzyme(Kcat)  (Read 45149 times)

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Offline Prozac

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Calculating turn over number of an Enzyme(Kcat)
« on: June 14, 2010, 10:27:03 PM »

Any Hints as to how to approach this calculation

Calculate the kcat of Enzyme 2, given the following data. 

Vmax  =  40,000 μmoles/sec, in an assay mixture of 1 mL

Amount of enzyme used in one assay (1 mL)  =  5 μL of a 1 mg/mL solution of enzyme

MW of the enzyme = 50,000 gm/mol

Km of the substrate  =  3 mM



My Approach

Kcat= Vmax/Et


I know my Vmax but I dont know how to find Et

Offline Yggdrasil

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Re: Calculating turn over number of an Enzyme(Kcat)
« Reply #1 on: June 15, 2010, 11:06:35 AM »
Et is the concentration of enzyme in moles/L.  You start with 5µL of a 1mg/mL solution of enzyme, and dilute this in 1mL.  What is the concentration now in terms of mg/mL?  What is that concentration when you convert it to moles/L?

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