A 0.64 g sample containing both NaCl and NaBr gives a precipitate AgCl and AgBr that weighs 0.5269 g. Another 0.64-g sample is titrated with 0.1084-F AgNO3, requiring 27.52 mL. Calculate the percentages of NaCl and NaBr in the sample.
Formula Mass: NaCl = 58.442 ; NaBr = 102.89 ; AgCl = 143.32 ; AgBr = 187.77
I'm having a problem how to use the moles of Ag+ that I'll be getting from the highlighted part.