20ml of 0.2 M MnSO4
are completely oxidised by 16ml ok KMnO4
of unknown normality each forming Mn+4
oxidation state. Find out the normality and molarity of KMnO4
I know that M1
Solving this equation, i get:
I also know that Normality=Molarity * valency factor
So, Normality=0.25*4 (Due to the presence of Mn+4
Hence, Normality of KMnO4 solution is 1.
But the answer given at the back is:
Normality = 0.5
Molarity = 0.167
Is there any mistake in my calculation?