Can you post the question exactly
as it is written. It is confusing as you've written it as it seems to contain irrelevant information and the numbers look as though they don't add up.
Exactly 1100 g alpha hydrate is mixed with water.
1100 g or 110 g?
I figured out that the whole system has 100g glucose on anhydrous basis and 30g of alpha and 80g of beta (80g of total glucose) in solution.
I agree with the green bit, but the red bit makes no sense... 30+80 = 110 not 80...
If the total amount of glucose added is 100 g (based on anhydrous) and the solution has mass 160 g you can now calculate:
1. The mass of glucose in solution
2. The mass of glucose (based on anhydrous) not in solution
Now you need to know which form of glucose precipitates from water in order to calculate the mass of solid. I am surprised that this is not given in the question, so I assume you are supposed to know that it is the alpha hydrate. As a side point, the anomeric ratio of aqueous glucose is completely irrelevant as far as I can see.