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Topic: A rock  (Read 13590 times)

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Offline typhoon2028

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Re: A rock
« Reply #15 on: August 26, 2010, 02:55:20 PM »
An object placed in water will displace a volume of water equal to the volume of the object.

This is correct:
17-11.3=5.7 ml

1 ml = 1cm³

12.1g/5.7cm³ = 2.12g/cm³

The way you want to do it would give you a rock with a density lower than water.  I don't see many floating rocks!

Offline Borek

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Re: A rock
« Reply #16 on: August 26, 2010, 05:04:39 PM »
12.1g/5.7cm³ = 2.12g/cm³

12.1g/5.7cm³ = 2.12g/cm³

What it is with you people, is it so hard to read forum rules? We don't give exact answers.
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Offline JGK

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Re: A rock
« Reply #17 on: August 26, 2010, 05:20:41 PM »
12.1g/5.7cm³ = 2.12g/cm³

12.1g/5.7cm³ = 2.12g/cm³

What it is with you people, is it so hard to read forum rules? We don't give exact answers.

Probably down to frustration BoreK; the OP seems to  have a rock like density and is incapable of recognizng help when given. Even spoon feeding the correct answer once didn't seem to take.
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Offline typhoon2028

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Re: A rock
« Reply #18 on: August 27, 2010, 10:21:01 AM »
I just copied an already posted answer.

My point was the poster should have logically figured out his density answer was incorrect.

Offline typhoon2028

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Re: A rock
« Reply #19 on: August 27, 2010, 10:23:58 AM »
Also, not to be technical about rules, but I do not believe the answer is exact.  I believe the significant digits in the answer I posted are incorrect.

Offline 408

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Re: A rock
« Reply #20 on: August 27, 2010, 04:38:27 PM »
the OP seems to  have a rock like density

 ;D

d=m/v

mass-you have
 volume- of the rock, which is equal to that of the water displaced.

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