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Topic: Chemical Equilibrium  (Read 2866 times)

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Offline awandering

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Chemical Equilibrium
« on: September 07, 2010, 07:31:44 AM »
I have been given a question to calculate the Chemical equilibrium for ammonia.

Using the formula
N2 plus 3H2 -> 2NH
Where
N2 equals 1.3 X10-3
H2 1.1 X10-2
NH3 equals 9.8 X 10-1 all with mol dm-3?

I used the equation K = [NH3]^2 / [N2] X [H2]^3

The only problem is i get a figure in the region I was not expecting. I have repeated the calculation several times.

The Answer I get is 5.5 X 10 ^9 mol^2 dm^6

This value seems way of the mark for this equation given that the temperature is given at 25 Degress C. I would expect a value around 6.4 x 10^2

Can anyone help -- or see where im going wrong in my calculations

Offline Borek

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Re: Chemical Equilibrium
« Reply #1 on: September 07, 2010, 08:59:44 AM »
For the given data Kc value that you got seems to be the correct one.
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Offline awandering

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Re: Chemical Equilibrium
« Reply #2 on: September 07, 2010, 09:39:27 AM »
do the units seem correct?


Offline Borek

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Re: Chemical Equilibrium
« Reply #3 on: September 07, 2010, 09:44:11 AM »
Good point. No. You ate minuses.
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Offline awandering

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Re: Chemical Equilibrium
« Reply #4 on: September 07, 2010, 10:40:12 AM »
K= 5.5 X 109mol -2 dm6?

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