Sorry correction. It's NaCl not NaOH.
Ok I tried doing it and this is what I got. I'm not sure if it's correct or not. If it isn't then some guidance would be great.
I converted 10μL BSA into 0.01 mL BSA.
The total solution (BSA + NaCl) is 50 μL = 0.05 mL. I didn't include the volume of the Bradford reagent as I thought the volume would be too small anyway..? Please correct me if I am wrong.
So this is how I did the calculation: 0.01 mL BSA in 0.05 mL solution
(0.01 mL x 1 mg/mL)/0.05 mL = 0.2 mg/mL
0.2 mg/mL x 1000 μg/mg = 200 μg/mL
But they wanted the concentration to be in μg/tube so I figured since 200 μg is present in just 1 mL and there is 0.05 mL per tube (total solution), I would have to multiply that amount by the total solution to get how much protein is there in the entire tube.
200 μg/mL x 0.05 mL/tube = 10 μg/tube --> Answer!
Am I right in any of this, lol? Please let me know!