Now, we still have the Cl-
in solution and have oxidized the Sn to a 2+
state. Why does stannous iodide now crystalize instead of stannous chloride? Since chloride is a better nucleophile won't it bond preferentially?SnI4 case:
The acetic anhydride will react with any water in the system to produce more acetic acid. Is H+
again acting as an oxidizing agent in this reaction? If so, why is this Sn complex oxidized to a 4+ state? The higher heat? and why is this system allowed to interact with atmospheric oxygen?