What is the orbital hybridization of SF6?
I understand SF6 is octahedral, but I am not sure how it is able to form 6 bonds. My natural assumption is that it is hybridized by spppdd, but I am told by other sources that there is absolutely no d orbitals on this energy level.
This goes against what I thought about Be, it has 3 p orbitals, but they don't get filled unless it is hybridized I believe, e.g. BeCl2.
Please help me demystify this dilemma.