April 28, 2024, 06:47:06 PM
Forum Rules: Read This Before Posting


Topic: Subject: Electronic Transition in a Hydrogen Atom  (Read 3116 times)

0 Members and 1 Guest are viewing this topic.

Offline big

  • Regular Member
  • ***
  • Posts: 79
  • Mole Snacks: +1/-0
Subject: Electronic Transition in a Hydrogen Atom
« on: October 12, 2010, 08:08:35 AM »
Which electronic transition in a hydrogen atom occurs with an energy that corresponds to visible light?
A)   n=2 :rarrow: n=1
B)   n=5 :rarrow: n=1
C)   n=4: rarrow: n=2
D)   n=6 : rarrow: n=3

The answer says that it is C, but why isn’t B the right answer if it gives off the more energy?

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27665
  • Mole Snacks: +1801/-410
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Subject: Electronic Transition in a Hydrogen Atom
« Reply #1 on: October 12, 2010, 08:36:50 AM »
Too low energy and you are emitting IR, too much and you are in the UV range.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Offline big

  • Regular Member
  • ***
  • Posts: 79
  • Mole Snacks: +1/-0
Re: Subject: Electronic Transition in a Hydrogen Atom
« Reply #2 on: October 12, 2010, 03:10:59 PM »
How do you know then which electronic transitions will give off which forms of radiation if you were just given something like, say, n=3  :rarrow: n=1?

Offline opti384

  • Full Member
  • ****
  • Posts: 434
  • Mole Snacks: +33/-25
  • Gender: Male
    • In the Search for the Laws of Nature
Re: Subject: Electronic Transition in a Hydrogen Atom
« Reply #3 on: October 12, 2010, 08:46:31 PM »
You should know about the Lyman Series, Balmer Series, Paschen Series. When the excited electron transits to n=1, UV is emitted and the series of light are called the Lyman Series. Balmer Series are visible light emitted when the electron transits to n=2, the Paschen Series are IR from electron transited to n=3.

Sponsored Links