[madknt]

Question: an unknown substance is emirically determined to be 40.00% Carbon by weight, 6.57% hydrogen, and 53.33% oxygen. Its molecular weight is roughly 55g/mol. determine the molecular formula and its correct molecular wight.

My Working So Far:
40% C = 22g = 1.8C
6.67% H = 3.66g =3.6H
53.33% O = 29.3315g = 1.8O

therefore molecular formula is CH20..
is this correct so far and how do i find the correct molecular weight?

[asqa]

My Working So Far:
40% C = 22g = 1.8C
6.67% H = 3.66g =3.6H
53.33% O = 29.3315g = 1.8O

therefore molecular formula is CH20..

your working is  correct but molecular formula what you written is wrong.In the molecular formula no of element is whole number not a decimal one like 1.8C.So rounding off what value you got e.g. 3.6H =4H,1.8O=2 like this

finally you will get C2H4O2
the above is actual formula then find out molecular weight by applying atomic weight of each element

calculate and tell me answer?

[madknt]

thanks for your help:

the molecular weight of C2H4O2 would be 60.06 g

[asqa]

good
keep it up