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Topic: Work  (Read 3594 times)

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Offline wannabe1

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Work
« on: October 19, 2010, 01:48:37 AM »
So we are told to calculate the value of w(work) for the following system: 2NaN3(s) :rarrow:2Na(s)+3N2(g)
if 21.5g of NaN3 reacts completely at 1atm and 22.0 degrees celsius

so I know that w=(change in n)RT

So I know when 21.5g of NaN3, that means 0.496 moles of N2 are produced and 0.331 moles of Na.
And also 21.5g of NaN3 is 0.331 moles of NaN3.
I am stuck from here and am not sure what I did is right so far.

Offline Borek

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Re: Work
« Reply #1 on: October 19, 2010, 04:14:21 AM »
so I know that w=(change in n)RT

Change of n of what?
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Offline wannabe1

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Re: Work
« Reply #2 on: October 19, 2010, 11:47:51 AM »
this is jsut using the ideal gas law, PV=nRT
and w=-PV
so using those too I get w=nRT

Offline Borek

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Re: Work
« Reply #3 on: October 19, 2010, 12:13:14 PM »
What is n in this equation, and how it is related to the question?
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Offline wannabe1

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Re: Work
« Reply #4 on: October 19, 2010, 12:18:36 PM »
would n represent the change in grams of the solid?

Offline wannabe1

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Re: Work
« Reply #5 on: October 19, 2010, 03:11:12 PM »
actually it would represent the amount of gas produced I believe

Offline wannabe1

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Re: Work
« Reply #6 on: October 19, 2010, 03:28:45 PM »
Never mind I solved it.  Thanks for your help.

Offline Borek

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Re: Work
« Reply #7 on: October 19, 2010, 04:56:04 PM »
actually it would represent the amount of gas produced I believe

And that's the answer I hoped to hear :)
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