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Topic: Calculations regarding a reactor reaction  (Read 3416 times)

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Offline idieh

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Calculations regarding a reactor reaction
« on: October 21, 2010, 11:51:08 AM »
Well, i got a new exercise by my teacher, but it seems to be more technical and mathematical which isn't my cup of tea to be honest :D.

Unsaturated Hydrocarbons shall react to saturated hydrocarbons in a catalyzed reaction.
HCu + H2  :rarrow: HCs

simple sketch of the whole thing

1. Reactor: 2,5mm Radius and 70mm length (cylinder) filled with the catalyst. No commingling(?) and 50% of the Volume is perfused. What is the real Volume of the Reactor?
Guess: V = pi * 2,5mm2 * 70mm divided by 2 because only 50% of the volume is perfused.

2.  Table of measured data
Given:
Flow Rate @ Detector 2 (D1) = constant 28ml/min
Pressure before adding the unsaturated hydrocarbons (P) = 102,2 kPa
steam pressure of the unsaturated hydrocarbon (Pu) = 6,392 kPa - Temperature = 310 K

Calculate...
i. The flow rate after adding the unsaturated hydrocarbons (DA)
ii. The flow rate through the reactor (Temperature = 438 K)
iii. The mean dwell time (measured data table!!!!)

Given for i.


Guess:
i. Just put in the given data for the pressures P and Pu. I'm not sure about D0. I would calculate the average Flow Rate of the D0 values.

ii. I have no clue. Only thing I noticed is that perhaps the steam pressure (Pu) has to change, because the temperature of the reactor is 438 K and not 310 K. So if the steam pressure is necessary it's probably 9,0312 kPa. (6,392 kPa devided by 310 K and multiplied with 438 K)

iii. No Clue.


Please help me and I guess that there will be some problems understanding my text, so please ask if there are any problems.

Offline idieh

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Re: Calculations regarding a reactor reaction
« Reply #1 on: October 21, 2010, 06:21:30 PM »
Don't know why, but I can't edit my post.
Thought about it and have a few ideas.

i.
As I said before. Just put in the given values for the pressure and the average Flow Rate D0.
Average Flow Rate D0 = 52,57 ml/min

DA = 55,86 ml/min

ii.
I really don't know.
I would simply add the constant 28ml/min to D0 = 80,57 ml/min 
And as I said before the steam pressure has to change because the temperature changes.

DAreactor = 87,7 ml/min

iii.
I just took the reactor's volume and divided it by the average Flow Rate D0 or by the average Flow Rate + the constant 28,00 ml/min
= 0,78s or 0,51s


please help, I really don't have a clue. Just did it how it seemed to be logical to me.

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