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Topic: Hexamine Formation question  (Read 5763 times)

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Dinosaur_uk

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Hexamine Formation question
« on: August 29, 2005, 09:04:21 AM »
Hi there,

I have been trying to find out what are the reacting conditions for this reaction for a while...does anyone have an idea?

4NH3 + 6CH2O ? (CH2)6N4 + 6H2O


Blueshawk

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Re:Hexamine Formation question
« Reply #1 on: August 29, 2005, 10:24:28 AM »
Try this website...  Hope it helps


http://formalin-process.com/hexamine.html

Dinosaur_uk

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Re:Hexamine Formation question
« Reply #2 on: August 29, 2005, 12:11:25 PM »
Hmmm

but it doesn't tell what is the conditions for the fomation of hexamine...

hmmm how can i find this out

Blueshawk

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Re:Hexamine Formation question
« Reply #3 on: August 29, 2005, 03:18:59 PM »
Srry no luck.

It is hard to find the formation of hexamine, but I can find what they use it for :)

Offline HP

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Re:Hexamine Formation question
« Reply #4 on: August 30, 2005, 11:13:54 AM »
Just mix the formalin solution(35%CH2O) with the amonia(25%) and evaporate it under reduced pressure on water bath to dryness.Then you will see the colorless crystalls of your urotropine :P
You may precrystalize tem in ethanol. This reaction proceeds completely and is used for determination of formaldehyde.
xpp

Dinosaur_uk

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Re:Hexamine Formation question
« Reply #5 on: August 30, 2005, 03:33:35 PM »
Will this form in waste water?

or will the concentrations will be too low?

Offline HP

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Re:Hexamine Formation question
« Reply #6 on: August 30, 2005, 03:46:58 PM »
Yes i think this reaction will proceed well and in low concentrations of CH2O but then your waste water will be poluted with amonia for some time and uf that could be bad idea for your purpose i think  ;) Urotropine is water soluble too and it slowly release  free formaldehyde thats why its used in medicine as good antiseptic...
xpp

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