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Topic: Calculation of Enthalpy of neutralization  (Read 7319 times)

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SudheerBallare

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Calculation of Enthalpy of neutralization
« on: August 27, 2005, 01:10:31 PM »
hi friends,
I have been trying to solve the following problem for quite some time now and feel exhausted with the efforts now.

A waste containing 1% sulfuric acid (10,00mg/L) is neutralized by adding a concentration of lime slurry [ made by dissolving Ca(OH)2 (s) in water ]. if the water temperature is 15C before neutralization, what is it after neutralization?

[ well i was able to calculate enthalpy of neutralization as 55.85 kJ/mol but couldn't get thru to the temperature part. Aslo the answer is 17.7C but i don't know how to reach it.]
Any help provided will be gratefull acknowledged.

thnx

Offline Mitch

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Re:Calculation of Enthalpy of neutralization
« Reply #1 on: August 27, 2005, 01:47:05 PM »
I would of converted kJ to calories. And the amount of heat required to increase the temperature by 1 degree is defined as 1 calorie. But this method still won't get you the correct answer. ;)
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Offline sdekivit

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Re:Calculation of Enthalpy of neutralization
« Reply #2 on: August 27, 2005, 02:49:09 PM »
you must use the formula Q = c * m * delta T and calculate the heat released by the neutralization that is taken up by the solution.

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Re:Calculation of Enthalpy of neutralization
« Reply #3 on: August 27, 2005, 02:52:14 PM »
you must use the formula Q = c * m * delta T and calculate the heat released by the neutralization that is taken up by the solution.

Or you could use sdekivit textbook approach. ;)
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