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Topic: Equilibrium Problem  (Read 2864 times)

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Offline sinthreck

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Equilibrium Problem
« on: November 07, 2010, 11:28:23 PM »
Quote
A major contributor to global warming is increased emissions of CO2. Consider the equilibria below:
CaCO3(s) + CO2(aq) + H2O(l)  ::equil:: Ca2+(aq) + 2HCO3 -(aq)
CaCO3(s)  ::equil:: Ca2+(aq) + CO3 2-(aq)    ΔH = -ve
Which statement is true:
(c) The increased CO2 concentration in the ocean is causing a decrease in the pH.

This is my interpretation of the problem:

If you increase CO2(aq), the RHS of the first equation becomes favourable, hence Ca2+ increases.

Since Ca2+ increases, the LHS of the second equation becomes favourable, hence CO32- which is basic is reduced.

Because you reduce the concentration of CO32-, the pH decreases.

Is that correct ?

Offline Borek

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Re: Equilibrium Problem
« Reply #1 on: November 08, 2010, 03:08:21 AM »
I have yet to see example of solution which becomes more basic (ie pH goes up) when you add acid.
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Offline sinthreck

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Re: Equilibrium Problem
« Reply #2 on: November 08, 2010, 04:15:58 PM »
lol - how silly of me, this is my second attempt at an explanation:

For every one mole of CO2(aq) which you dissolve, you create 1 mole Ca2+(aq) and 2 moles of HCO3-(aq).
This is causing a decrease in the pH because HCO3-(aq) is a proton acceptor.

Looking to the second equation. Since you created the 1 mole of Ca2+(aq) it reacts with 1 mole of CO32-(aq) to create CaCO3(s).

The net result is that you have:
1) created 2 moles HCO3-(aq)
2) used 1 mole of CO32-(aq)

Hence, overall this is an increase in basic anions which results in a DECREASE in pH.

Offline sinthreck

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Re: Equilibrium Problem
« Reply #3 on: November 08, 2010, 04:23:12 PM »
ok, well I just said the exact same thing :(

so I've looked up on google that when you dissolve CO2 in water, you get carbonic acid:

CO2 + H2O ==> H2CO3

I can't really see that in my equation from the first question. It produces HCO3- which I think is the conjugate base of H2CO3

Unfortunately, in the exam (which is in 2 days times) - I can't use google...

Offline Borek

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Re: Equilibrium Problem
« Reply #4 on: November 08, 2010, 04:57:22 PM »
This about it this way. Calcium carbonate dissolves to some small extent, producing CO32-:

CaCO3 <-> Ca2+ + CO32-

At the same time carbon dioxide dissolves in water, producing carbonic acid. So now you have carbonic acid and CO32- in solution:

H2CO3 + CO32- <-> 2HCO3-

You may also write carbonic dissociation first stage

H2CO3 <-> H+ + HCO3-

and

H+ + CO32- <-> HCO3-

which yields exacltly teh same result.

But as I wrote earlier - no matter what is the system involved, when you add acid, pH goes down, when you add base, pH goes up.
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