hi everybody
i am doing a iodometric titration of copper sulfate as specified by the USP .
Place about 650 mg of Cupric Sulfate in an accurately weighed container fitted with a ground-glass stopper, dry, allow to cool in a desiccator, and weigh again to obtain the weight of the specimen. Dissolve in 50 mL of water, add 4 mL of 6 N acetic acid and 3 g of potassium iodide, and titrate the liberated iodine with 0.1 N sodium thiosulfate VS, adding about 2 g of potassium thiocyanate and 3 mL of starch TS as the endpoint is approached. Perform a blank determination, and make any necessary correction. Each mL of 0.1 N sodium thiosulfate is equivalent to 15.96 mg of CuSO4.
when i use this conversion factor , i am supposed to get the percentage purity of the
copper sulfate .
assuming the titration consumes 6 ml , i would get 99% purity .
form this how do i calculate the percentage of copper in it ?