April 26, 2024, 04:58:44 AM
Forum Rules: Read This Before Posting


Topic: Magnetite  (Read 5361 times)

0 Members and 1 Guest are viewing this topic.

Offline LHM

  • Full Member
  • ****
  • Posts: 144
  • Mole Snacks: +1/-3
Magnetite
« on: November 26, 2010, 04:35:06 PM »
Magnetite, which has the formula Fe3O4, is comprised of iron(II) oxide and iron(III) oxide. What is the ratio of iron(II) ions to iron(III) ions in magnetite?

The answer is 1:2, but I fail to see how that's the answer. Isn't Fe3O4 also known as Fe2O3*FeO? so I figured that the ratio must be 1:1, but it's not. Where's the flaw in my logic?

Offline Schrödinger

  • Chemist
  • Sr. Member
  • *
  • Posts: 1162
  • Mole Snacks: +138/-98
  • Gender: Male
Re: Magnetite
« Reply #1 on: November 27, 2010, 12:52:46 AM »
Isn't Fe3O4 also known as Fe2O3*FeO?

Yes it is.
One molecule of Fe2O3 has 2 Fe(III) atoms and one molecule of FeO has one Fe(II) atom.

That's why the ratio is 1:2
"Destiny is not a matter of chance; but a matter of choice. It is not a thing to be waited for; it is a thing to be achieved."
- William Jennings Bryan

Offline Borek

  • Mr. pH
  • Administrator
  • Deity Member
  • *
  • Posts: 27664
  • Mole Snacks: +1801/-410
  • Gender: Male
  • I am known to be occasionally wrong.
    • Chembuddy
Re: Magnetite
« Reply #2 on: November 27, 2010, 05:34:22 AM »
Where's the flaw in my logic?

You solved different question. It doesn't ask about oxide:oxide ratio, but Fe(II):Fe(III) ratio.
ChemBuddy chemical calculators - stoichiometry, pH, concentration, buffer preparation, titrations.info

Sponsored Links