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Topic: What is the pH of....  (Read 2251 times)

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Offline hobomojo

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What is the pH of....
« on: December 06, 2010, 09:50:19 AM »
What is the pH if a 50mL of an aqueous solution made with 1.00g of heroine(Formula weight=269.42) The pKa=8.02?

Could someone show me how to solve this problem? I've been working practice problems for my exam and I don't know how to do this one.

Thanks!
« Last Edit: December 06, 2010, 10:09:00 AM by hobomojo »
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Offline rabolisk

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Re: What is the pH of....
« Reply #1 on: December 06, 2010, 11:10:19 AM »
Just treat heroin as any acid that would normally dissociate in water, and set up the equilibrium. You are (indirectly) given all the data you need.
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Offline hobomojo

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Re: What is the pH of....
« Reply #2 on: December 06, 2010, 11:59:45 AM »
I'm not sure on how to do that : /

I got (1.00g)/(269.42g)=.0037

Then I got
(x^2)/(.0037-x) but I'm not sure what to do after this point
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Offline rabolisk

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Re: What is the pH of....
« Reply #3 on: December 06, 2010, 04:35:49 PM »
What is x2/(.0037-x) equal to?

Understand the chemistry before anything else.
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