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Topic: balancing Redox equations  (Read 2907 times)

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Offline Asum

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balancing Redox equations
« on: December 09, 2010, 02:20:24 PM »
I'm supposed to find the ox. no of Cl on each side:

Cl2 (g) ---> Cl - (aq) + ClO-3 (aq)

I know that on the left the ox. no is 0 and Cl - on the right has -1
but what's the ox. no to Cl of ClO-3 ? And how do you find it?

thx

Offline rabolisk

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Re: balancing Redox equations
« Reply #1 on: December 09, 2010, 02:36:41 PM »
A useful rule is that the oxidation number of oxygen is usually -2, except when it is bonded to fluorine (which is more electronegative) or is a peroxide or superoxide.

Offline opti384

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Re: balancing Redox equations
« Reply #2 on: December 09, 2010, 09:46:57 PM »
You are right rabolisk but in this case I think the oxygen will stick to the original -2 because oxygen is more electronegative than Cl.

Offline Borek

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Re: balancing Redox equations
« Reply #3 on: December 10, 2010, 04:20:20 AM »
You are right rabolisk but in this case I think the oxygen will stick to the original -2 because oxygen is more electronegative than Cl.

That's what he wrote in case you missed it.
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Offline Fluorine

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Re: balancing Redox equations
« Reply #4 on: December 10, 2010, 05:13:49 AM »
how do you find it?

Check this link for a easy to follow set of rules to help you determine oxidation states. When you're unsure if an element can take that state try Wikipedia's "list of oxidation states of elements".
I'm still learning - always check my work/answer.

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