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Topic: Structure of Sulphuric acid  (Read 4408 times)

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hya_been

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Structure of Sulphuric acid
« on: September 02, 2005, 03:57:09 PM »
I've been looking at the structure of sulphuric acid, and I don't understand how it can have that many bonds...wouldn't its valence have 12 electrons then? Does it have anything to do with SO4 having a 2- charge?  Where do polyatomic Ions gain electrons from, and how do you represent the gained ones structurally?


« Last Edit: September 02, 2005, 05:03:20 PM by hya_been »

Offline Mitch

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Re:Structure of Sulphuric acid
« Reply #1 on: September 02, 2005, 06:15:47 PM »
Sulfur can exceed the octet rule.
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Offline Yggdrasil

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Re:Structure of Sulphuric acid
« Reply #2 on: September 02, 2005, 09:52:53 PM »
Since sulfur is in the third period, it has the 3d orbitals available to accept electrons.  So, when bonding, sulfur will occasionally utilizes 2 d-orbitals to form six sp3d2 orbitals, allowing it to form six covalent bonds.

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Re:Structure of Sulphuric acid
« Reply #3 on: September 02, 2005, 10:08:02 PM »
D-orbitals will not be involved, its actually a rather complicated explanation.
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demt

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Re:Structure of Sulphuric acid
« Reply #4 on: September 03, 2005, 09:31:57 PM »
the way I understood it, from my first year at uni, was that the higher oxidation state was attributed to the promotion of one 3p and one 3s electron each to an empty 3d orbital, giving a total of six sp3d2 hybrids which, after covalent bonding producing a compound from which sulphurs ox state is +12.

If this is NOT the case, then what is the mechanism by which sulphur achieves its +12 state? I can't see how it would achieve this state without the use of d electrons. If the explanation is too long, could someone point me in the right direction as I am interested in finding this out.

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