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Topic: Reducing a Formula  (Read 3623 times)

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Offline XxslbabesxX

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Reducing a Formula
« on: September 02, 2005, 10:18:32 PM »
This may be a silly question, but I was wondering why, for example, Cr2O6 has to be reduce to CrO3 (according to my teacher), but for something like Octane, C8H18, it does not reduce to C4H9.

Offline Yggdrasil

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Re:Reducing a Formula
« Reply #1 on: September 03, 2005, 12:43:27 AM »
It has to do with whether the compound is ionic or covalent.  In ionic compounds, the formula represents the ratio of atoms in the crystaline solid.  There are no actual molecules of CrO3.  Therefore, the empirical forumla is used.  However, in a covalently-bound compound, actual molecules do exist and these molecules consist of the exact number of atoms described in the molecular structure.

Offline XxslbabesxX

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Re:Reducing a Formula
« Reply #2 on: September 03, 2005, 11:10:12 PM »
Thank you for your help :)

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