Hey Guys, thanks for the answers.
Juan: physisorption does not require activation energy, however, chemisorption indeed does. But when a molecule is chemisorbed, you break the same bonds which you break with a homogeneous catalyst. However, there should be something here, what I do not see, I think...
If we keep the amount of the homogeneous catalyst and the active sites of a heterogeneous catalyst equal, I would expect the same results. That is, you only should increase the number of active sites (higher dispersion, metal loading, cat amount...) and keep the temperature low.
Stepan: I do not think it has to do anything with volatility. I think some industry guys were very happy if ammonia synthesis would run at room temperature. However, I can accept that high temperature is not _always_ needed.
There should be something around chemisorption vs steps usual in homogeneous catalysis (insertion, reductive elimination, oxidative addition...). Any idea?
Thanks again
crt