March 28, 2024, 07:03:23 PM
Forum Rules: Read This Before Posting


Topic: Answer Verification : finding the volume occupied by 1.0 kg of CO...  (Read 3779 times)

0 Members and 1 Guest are viewing this topic.

afchick7689

  • Guest
Heres the problem, my work, and my answer--

if someone could please check over this, i think i must have made an error somewhere because the answer seems very large...

What would be the volume occupied by 1.0 kg of carbon monoxide at 700 °C and 0.1 atm?

PV= nRT

0.1 atm * V = n * 0.0821 * (700 + 273.15)
To find n --
1.0 kg CO  | 1000 g CO = 1000 g CO
   | 1 kg CO
molar mass of CO = (12.01) + (16.00) = 28.01g
1000 g CO |   1 mol CO    =    35.702 mol CO
   | 28.01 g CO
...SO:
0.1 atm * V = 35.702 mol CO*0.0821*(700 + 273.15)
.01 V = 2852.43
V= 285243.32 L (W/ SIG FIGS: 300000 L)

Offline Yggdrasil

  • Retired Staff
  • Sr. Member
  • *
  • Posts: 3215
  • Mole Snacks: +485/-21
  • Gender: Male
  • Physical Biochemist
Re:Answer Verification : finding the volume occupied by 1.0 kg of CO...
« Reply #1 on: September 04, 2005, 04:04:18 PM »
The second-to-last line should read:

0.1 V = 2852.43

Which is why your answer is off by a factor of 10.

afchick7689

  • Guest
Re:Answer Verification : finding the volume occupied by 1.0 kg of CO...
« Reply #2 on: September 05, 2005, 10:02:48 AM »
thanks!

Sponsored Links